若x/2=y/3=z/6,求(3x+4y-2z)/(x-y+3x)的值
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若x/2=y/3=z/6,求(3x+4y-2z)/(x-y+3x)的值
若x/2=y/3=z/6,求(3x+4y-2z)/(x-y+3x)的值
若x/2=y/3=z/6,求(3x+4y-2z)/(x-y+3x)的值
设k=x/2=y/3=z/6;
则x=2k,y=3k,z=6k,
所以(3x+4y-2z)/(x-y+3z)=(6k+12k-12k)/(2k-3k+18k)=6/17.
PS:题目可能有误,我作了修正.
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