求∫xcos²x dx
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求∫xcos²x dx
求∫xcos²x dx
求∫xcos²x dx
∫xcos²x dx
=∫x*(1+cos2x)/2dx
=∫x/2dx+∫xcos2x/2dx
=x^2/4+ ∫x/4dsin2x
=x^2/4+ x*sin2x/4 -∫sin2xdx/4
=x^2/4+x*sin2x/4+cos2x/8+C(常数)