八年级下册数学题(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)

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八年级下册数学题(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)
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八年级下册数学题(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)
八年级下册数学题
(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1
(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)-3x(3x+y)
要过程 谢谢了
现在只要1,2,6题 其他不用了

八年级下册数学题(1)a²-(x²+2x+1)(2)(y+1)²-9(y-1)²(3)(x²-2x)²+2(x²-2x)+1(4)(x²+4)²-16x²(5)a²-8a²b²+16b四次方(6)(3x+y)(2x-3y)
a²-(x²+2x+1)=a²-(x+1)²=(a+x+1)(a-x-1)
(2)(y+1)²-9(y-1)²=(y+1+3(y-1))(y+1-3(y-1))=(4y-2)(4-2y)
(3)(x²-2x)²+2(x²-2x)+1=(x²-2x+1)²=(x-1)^4
(4)(x²+4)²-16x²=(x²+4-4x)(x²+4+4x)=(x+2)²(x-2)²
(5)a²-8a²b²+16b四次方=?
(6)(3x+y)(2x-3y)-3x(3x+y)=6x²+2xy-9xy-3y²-9x²-3xy=-3x²-3y²-10xy=-(x+3y)(3x+y)
第五题是不是a^4-8a²b²+16b^4=(a²-4b²)²

题目问什么?化简成多项式还是因式分解?因式分解(1)a²-(x²+2x+1)=a²-(x+1)²=(a+x+1)(a-x-1)
(2)(y+1)²-9(y-1)²=(y+1)²-(3y-3)²=(y+1+3y-3)(y+1-3y+3)=(4y-2)(-2y+4)=4(2y-1)(-y+2)
(3)(x&...

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题目问什么?化简成多项式还是因式分解?

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....无聊 加油自己写

是因式分解么?
1、a^2-(x^2+2x+1)=a^2-(x+1)^2=(a-x-1)(a+x+1)
2、(y+1)^2-9(y-1)^2=(y+1)^2-(3y-3)^2=(4y-2)(4-2y)
3、(x^2-2x)^2+2(x^2-2x)+1=(x^2-2x+1)^2=(x-1)^4
4、(x^2+4)^2-16x^2=(x^2+4+4x^2)(x^2+4-...

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是因式分解么?
1、a^2-(x^2+2x+1)=a^2-(x+1)^2=(a-x-1)(a+x+1)
2、(y+1)^2-9(y-1)^2=(y+1)^2-(3y-3)^2=(4y-2)(4-2y)
3、(x^2-2x)^2+2(x^2-2x)+1=(x^2-2x+1)^2=(x-1)^4
4、(x^2+4)^2-16x^2=(x^2+4+4x^2)(x^2+4-4x^2)=(5x^2+4)(4-3x^2)
5、[a^2-8(a^2)(b^2)+16b]^4=[(a-4b)^2]^4=(a-4b)^8
6、(3x+y)(2x-3y)-3x(3x+y)=(3x+y)(2x-3y-3x)=-(3x+y)(3y+x)

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