已知a²+b²-2a+8b+20=0,求2a+3b的值(过程)
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已知a²+b²-2a+8b+20=0,求2a+3b的值(过程)
已知a²+b²-2a+8b+20=0,求2a+3b的值(过程)
已知a²+b²-2a+8b+20=0,求2a+3b的值(过程)
a²+b²-2a+8b+20=0,
(a-1)²+(b+4)²=0
即
a-1=0,b+4=0
a=1,b=-4
所以
2a+3b
=2×1+3×(-4)
=2-12
=-10