因式分解m(x+y)²-4m(x-y)²..我纠结了3个小时了@@上学就得交了啊只剩7个小时了啦QAQ
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![因式分解m(x+y)²-4m(x-y)²..我纠结了3个小时了@@上学就得交了啊只剩7个小时了啦QAQ](/uploads/image/z/13693771-19-1.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3m%28x%2By%29%26%23178%3B-4m%28x-y%29%26%23178%3B..%E6%88%91%E7%BA%A0%E7%BB%93%E4%BA%863%E4%B8%AA%E5%B0%8F%E6%97%B6%E4%BA%86%40%40%E4%B8%8A%E5%AD%A6%E5%B0%B1%E5%BE%97%E4%BA%A4%E4%BA%86%E5%95%8A%E5%8F%AA%E5%89%A97%E4%B8%AA%E5%B0%8F%E6%97%B6%E4%BA%86%E5%95%A6QAQ)
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因式分解m(x+y)²-4m(x-y)²..我纠结了3个小时了@@上学就得交了啊只剩7个小时了啦QAQ
因式分解m(x+y)²-4m(x-y)²
..我纠结了3个小时了@@上学就得交了啊
只剩7个小时了啦QAQ
因式分解m(x+y)²-4m(x-y)²..我纠结了3个小时了@@上学就得交了啊只剩7个小时了啦QAQ
m(x+y)²-4m(x-y)²
=m[(x+y)²-4(x-y)²]
=m[(x+y)²-2²(x-y)²]
=m[(x+y-2(x-y))(x+y+2(x-y))]
=m[(-x+3y)(3x-y)]
=m(3y-x)(3x-y)
m(x+y)²-4m(x-y)²
原式=m(x+y)²-m(2x-2y)²
=m[(x+y)²-(2x-2y)²]
=m(3x-y)(3y-x)
先提出m来,剩下就好办了
原式=m(x²+2xy+y²-4x²+8xy-4y²)
=-m(3x²-10xy+3y²)
根据十字交叉,
1 -3
3 -1
----------
-9 -1
可以使,
原式=-m(x-3y)(3x-y)
=m(x-3y)(y-3x)