x+1/x=3 问X^2+1/X^2=?
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x+1/x=3 问X^2+1/X^2=?
x+1/x=3 问X^2+1/X^2=?
x+1/x=3 问X^2+1/X^2=?
x^2+1/(x^2)=(x+1/x)^2-2=3^2-2=9-2=7
x+1/x=3
所以(x+1/x)^2=x^2+1/x^2+2=9
所以x^2+1/x^2=7
(X+1/x)^2=9讲这个等式两边张开就可以了那 结果等于7
2^x+1=3^x 问x=?
(X+1)X(X+2)X(X+3)=504
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
X-1=2X,问x等于几?
x+1/x=3 问X^2+1/X^2=?
x/3-(3x+1)/2=4-(5x-3)/6 问x=?
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
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请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360
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X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
(x+1)/(x+2)+(x+8)/(x+9)解答x+1/x+2+x+8/x+9=x+2/x+3+x+7/x+8
X/1+X=3 求X^2/X^4 +X^2+1=?顺便问下