作业帮求证：tan(x+y)+tan(x-y)=sin2x/cosx*cosx-siny*siny
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/24 09:09:05
x){{f$iThWjjřyFZ Bȯ6IEi/N `Q&0H D , + kt4GÄ`jb ]rWVr&\H.EfҺ 8#B
uabP6H -p}Ztt`l$فb
求证：tan(x+y)+tan(x-y)=sin2x/cosx*cosx-siny*siny
求证：tan(x+y)+tan(x-y)=sin2x/cosx*cosx-siny*siny
求证：tan(x+y)+tan(x-y)=sin2x/cosx*cosx-siny*siny
tan(x+y)+tan(x-y)
=sin(x+y)/cos(x+y)+sin(x-y)/cos(x-y)
=[sin(x+y)cos(x-y)+cos(x+y)sin(x-y)]/[cos(x+y)cos(x-y)]
=sin2x/[(cosxcosy-sinxsiny)(cosxcosy+sinxsiny)]
=sin2x/[(cosx)^2(cosy)^2-(sinx)^2(siny)^2]
=sin2x/[(cosx)^2(cosy)^2-(1-(cosx)^2)(1-(cosy)^2)]
=sin2x/[(cosx)^2+(cosy)^2-1]
=sin2x/[(cosx)^2-(siny)^2]
得证
求证tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-a)tan(z-x)
求证tan(x+y)*tan(x-y)=tan^2x-tan^2y/1-tan^2xtan^2y
求证tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)tan(x-y)+tan(y-z)怎么化成tan〔（x-y）+(y-z)〕?
三角函数（请写出过程）求证：tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)
tan(x+y)=
求证tan(x+y)*tan(x-y)=(tan2x-tan2y)/(1-tan2xtan2y)
求证：tan(x+y)+tan(x-y)=sin2x/cosx*cosx-siny*siny
1 求证：tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)2 已知a+b+c=npai(n属于Z),求证：tan(a)+tan(b)+tan(c)=tan(a)tan(b)tan(c)（提示：在等式a+b=npai-b同时取正切）
第一题：α-β+r=nπ(n∈Z）,求证：tanα+tanβ+tanr=tanαtanβtanr第二题：求证 tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)
tan(x+y)等于什么?
y=tan|x|值域
y=tan(x平方)
tan等于x/y还是y/x
已知sin(2x+y)=5siny,(y不等于K派),求证;3tan=2tan(x+y)
如何证明 tan(x-y)+tan(y-z)+tan(z-x)=tan(x-y)tan(y-z)tan(z-x)
证明tan^2x=2*tan^2y+1,求证sin^2y=2sin^2x-1
tan方x=2tan方y+1,求证sin方y=2sin方x-1
y=tan（x+y) 求二阶导数