已知sinα=-3/5,α∈(-π/2,0),则tan(π/4-α)的值为
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已知sinα=-3/5,α∈(-π/2,0),则tan(π/4-α)的值为
已知sinα=-3/5,α∈(-π/2,0),则tan(π/4-α)的值为
已知sinα=-3/5,α∈(-π/2,0),则tan(π/4-α)的值为
sinα=-3/5,α∈(-π/2,0)
cosα=根号(1-sin^2)=根号[1-(-3/5)^]=4/5
tanα=sinα/cosα=-3/5 / (4/5) = -3/4
tan(π/4-α)=(tanπ/4-tanα)/(1+tanπ/4tanα)
=(1-tanα)/(1+tanα)
=(1+3/4)/(1-3/4)
=7