y=√1-2X+√2X-1+√(X-1)²则代数式(x+y)¹ºº=?

y=2x+√(1-x) 若√x-1-√1-x=(x+y)²先化简再求值：（1/2x）-(1/x+y)[x²-y²+(x+y/2x] 先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y 求导y=2x^3-3x+(√x)-1/x√x xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 y=arcsin(x/√1+x^2),求y' y=ln(x+√x^2+1),求y (2x-y)(x-y)/(x-2y)^其中X=1+√2,Y=1-√2 求值域 y=(x²-1)/(x²+x+1); y=2x-3+√(13-4x); y=(3x+2)/(x-1) 求值域 y=(x²-2)/(x²+x+1); y=2x-3+√(13-4x); y=(3x+2)/(x-1) 解方程组 x+y=1 |√(x+2)+y-√(x-2)+y|=2 |2x+y+1|+√2y+3x=0则x.y= y=(3x-1)/(x+1) (x>=5)值域 y=x-√(1-2x)值域 已知4x²+y²-4x-6y+10=0求（2/3x（√9x）+(y²√x/y³)×(x²√1/x×5x√y/x)的值 已知4x²+y²-4x-6y+10=0求（2/3x（√9x）+(y²√x/y³)-(x²√1/x-5x√y/x)的值 已知4x²+y²-4x-6y+10=0,求[(2/3)x√(9x)+y²√(x/y³)-(x²√(1/x)-5x√(y/x)的值 y=x√(1+x^2)+ln(x+√(1+x^2) 求dy y=x+√(x^2+1),求反函数.是log2[x+√(x^2+1)]！