4*10X+[(X+1)-2]-[10X+(X+1)]=58
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4*10X+[(X+1)-2]-[10X+(X+1)]=58
4*10X+[(X+1)-2]-[10X+(X+1)]=58
4*10X+[(X+1)-2]-[10X+(X+1)]=58
4*10X+[(X+1)-2]-[10X+(X+1)]=58
40x+x-1-11x-1=58
40x+x-11x=58+2
30x=60
x=2
x=2
化为40x+[x-1]-[11x+1]=58
41x-1-11x-1=58
30x=60
x=2
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