[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1
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[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1
[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1
[(x-y)^2+(x+y)(x-y)]÷2x,其中x=2011y=-1
[(x-y)^2+(x+y)(x-y)]÷2x
=(x-y)[(x-y)+(x+y)]÷2x
=(x-y)(x-y+x+y)÷2x
=2x(x-y)÷2x
=x-y
=2011-(-1)
=2011+1
=1012
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化简:[(x+y)(x-y)(x+y)^2-2y(x-2y)](-2y) 谢谢!