1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0

1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.
2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0

1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
1、(x²+y²)²-(x²+y²)-12=0
(x²+y²-4)(x²+y²+3)=0
x²+y²=4 x²+y²=-3 舍去
2、(x+m)(x+m+1)=0
x=-m x=-m-1