1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
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![1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0](/uploads/image/z/13900724-44-4.jpg?t=1.%E5%B7%B2%E7%9F%A5%28x%26%23178%3B%2By%26%23178%3B%29%28x%26%23178%3B-1%2By%26%23178%3B%29-12%3D0%2C%E6%B1%82x%26%23178%3B%2By%26%23178%3B%E7%9A%84%E5%80%BC.2.%E8%A7%A3%E6%96%B9%E7%A8%8Bx%26%23178%3B%2B%282m%2B1%29x%2Bm%26%23178%3B%2Bm%3D0+%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%842x-y%3D0%2Cx%26%23178%3B-y%26%23178%3B%2B3%3D0)
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1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.
2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
1.已知(x²+y²)(x²-1+y²)-12=0,求x²+y²的值.2.解方程x²+(2m+1)x+m²+m=0 解方程组2x-y=0,x²-y²+3=0
1、(x²+y²)²-(x²+y²)-12=0
(x²+y²-4)(x²+y²+3)=0
x²+y²=4 x²+y²=-3 舍去
2、(x+m)(x+m+1)=0
x=-m x=-m-1