n^(n+1/n)/(n+1/n)^n

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n^(n+1/n)/(n+1/n)^n
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n^(n+1/n)/(n+1/n)^n
n^(n+1/n)/(n+1/n)^n

n^(n+1/n)/(n+1/n)^n
∑n^(n+1/n)/(n+1/n)^n
lima = limn^(n+1/n)/(n+1/n)^n
= limn^n*n^(1/n)/[n^n*(1+1/n^2)^n]
= limn^(1/n)/(1+1/n^2)^n
= limn^(1/n)/[(1+1/n^2)^n^2]^(1/n)
=l imn^(1/n)/e^(1/n) =1 .
故该级数发散.