如图1,在直角梯形ABCD中,AD//BC,∠ABC=90°,BD=BC,E为CD的中点,AE的延长线交BC的延长线于F(高分求解)(1)试说明:EF=EA(2)如图2,过D作DG⊥BC于G,连接EG,试说明EG⊥AF
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![如图1,在直角梯形ABCD中,AD//BC,∠ABC=90°,BD=BC,E为CD的中点,AE的延长线交BC的延长线于F(高分求解)(1)试说明:EF=EA(2)如图2,过D作DG⊥BC于G,连接EG,试说明EG⊥AF](/uploads/image/z/13909007-47-7.jpg?t=%E5%A6%82%E5%9B%BE1%2C%E5%9C%A8%E7%9B%B4%E8%A7%92%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%2F%2FBC%2C%E2%88%A0ABC%3D90%C2%B0%2CBD%3DBC%2CE%E4%B8%BACD%E7%9A%84%E4%B8%AD%E7%82%B9%2CAE%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8EF%EF%BC%88%E9%AB%98%E5%88%86%E6%B1%82%E8%A7%A3%EF%BC%89%EF%BC%881%EF%BC%89%E8%AF%95%E8%AF%B4%E6%98%8E%EF%BC%9AEF%3DEA%EF%BC%882%EF%BC%89%E5%A6%82%E5%9B%BE2%2C%E8%BF%87D%E4%BD%9CDG%E2%8A%A5BC%E4%BA%8EG%2C%E8%BF%9E%E6%8E%A5EG%2C%E8%AF%95%E8%AF%B4%E6%98%8EEG%E2%8A%A5AF)
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