已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式判断f(x)的奇偶性
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![已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式判断f(x)的奇偶性](/uploads/image/z/13911895-55-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%26%23178%3B-1%29%3Dlogm%28x%26%23178%3B%2F2-x%26%23178%3B%29%28m%3E0%2C%E4%B8%94m%E2%89%A01%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%26%23178%3B-1%29%3Dlogm%28x%26%23178%3B%2F2-x%26%23178%3B%29%28m%3E0%2C%E4%B8%94m%E2%89%A01%EF%BC%89%E6%B1%82f%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E5%88%A4%E6%96%ADf%EF%BC%88x%EF%BC%89%E7%9A%84%E5%A5%87%E5%81%B6%E6%80%A7)
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已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式判断f(x)的奇偶性
已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式
已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)
求f(x)的解析式
判断f(x)的奇偶性
已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式已知函数f(x²-1)=logm(x²/2-x²)(m>0,且m≠1)求f(x)的解析式判断f(x)的奇偶性
函数f(x²-1)=logm[x²/(2-x²)](m>0,且m≠1)
函数有意义需
x²/(2-x²)>0
那么x²-2