设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离的比为定值a(a>0),求P点轨迹快,重赏设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离与到B点的距离比为定值a(a>0),求P点轨迹
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/19 21:56:47
![设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离的比为定值a(a>0),求P点轨迹快,重赏设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离与到B点的距离比为定值a(a>0),求P点轨迹](/uploads/image/z/13914292-4-2.jpg?t=%E8%AE%BEA%28-C%2C0%29%2CB%28C%2C0%29%28C%3E0%29%E4%B8%BA%E5%AE%9A%E7%82%B9%2C%E5%8A%A8%E7%82%B9P%E5%88%B0A%E7%82%B9%E7%9A%84%E8%B7%9D%E7%A6%BB%E7%9A%84%E6%AF%94%E4%B8%BA%E5%AE%9A%E5%80%BCa%28a%3E0%29%2C%E6%B1%82P%E7%82%B9%E8%BD%A8%E8%BF%B9%E5%BF%AB%2C%E9%87%8D%E8%B5%8F%E8%AE%BEA%28-C%2C0%29%2CB%28C%2C0%29%28C%3E0%29%E4%B8%BA%E5%AE%9A%E7%82%B9%2C%E5%8A%A8%E7%82%B9P%E5%88%B0A%E7%82%B9%E7%9A%84%E8%B7%9D%E7%A6%BB%E4%B8%8E%E5%88%B0B%E7%82%B9%E7%9A%84%E8%B7%9D%E7%A6%BB%E6%AF%94%E4%B8%BA%E5%AE%9A%E5%80%BCa%28a%3E0%29%2C%E6%B1%82P%E7%82%B9%E8%BD%A8%E8%BF%B9)
x){np3|cu7yڵH<jy}eg@=mؓԥlcS PՋ+^tj/iǓ}@!'d!Bv$K`6r<_`g3,ciO[;uL|-O.xڿEg]]/x>{}_NdW,4*t*5uv,.,*֨N3Ү3ՇEl!ږ/~ھܥO7lZdRO[=ٱ=
Ϧr*^ys3P@F 1 fʯ
设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离的比为定值a(a>0),求P点轨迹快,重赏设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离与到B点的距离比为定值a(a>0),求P点轨迹
设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离的比为定值a(a>0),求P点轨迹
快,重赏
设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离与到B点的距离比为定值a(a>0),求P点轨迹
设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离的比为定值a(a>0),求P点轨迹快,重赏设A(-C,0),B(C,0)(C>0)为定点,动点P到A点的距离与到B点的距离比为定值a(a>0),求P点轨迹
首先我要说你可能把题目输错了.
设P(x,y),则sqrt[(x+c)^2+y^2]/sqrt[(x-c)^2+y^2]=a
解出来就可以了.
其中sqrt为开方,y^2为y的平方.