若丨x+1丨+(x+y-2)²=0,求2x+y的值急
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若丨x+1丨+(x+y-2)²=0,求2x+y的值急
若丨x+1丨+(x+y-2)²=0,求2x+y的值
急
若丨x+1丨+(x+y-2)²=0,求2x+y的值急
根据题意得
x+1=0
x+y-2=0
∴x=-1
y=3
∴2x+y=-2+3=1