xy=1 x-y=0 x+y=?x²y²-4xy+5=4-x²-y²,求x+y
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xy=1 x-y=0 x+y=?x²y²-4xy+5=4-x²-y²,求x+y
xy=1 x-y=0 x+y=?
x²y²-4xy+5=4-x²-y²,求x+y
xy=1 x-y=0 x+y=?x²y²-4xy+5=4-x²-y²,求x+y
因为xy=1,x-y=0
所以(x+y)²-( x-y)²=4xy
(x+y)²=4
x+y=2
xy=1 x-y=0 x+y=? 这是给的条件还是?