抛物线C1 y*2=4x 的焦点F恰好是双曲线C2 x*2/a*2-y*2/b*2=1(a>0,b>0)的右焦点,且C1与C2焦点的连线过点F,则双曲线C2的离心率是多少y*2=4xx*2/a*2-y*2/b*2=1联立得b*2x*2-4a*2x-a*2b*2=0所以x1+x2=4a*2/b*2由抛物线得(x1+x
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![抛物线C1 y*2=4x 的焦点F恰好是双曲线C2 x*2/a*2-y*2/b*2=1(a>0,b>0)的右焦点,且C1与C2焦点的连线过点F,则双曲线C2的离心率是多少y*2=4xx*2/a*2-y*2/b*2=1联立得b*2x*2-4a*2x-a*2b*2=0所以x1+x2=4a*2/b*2由抛物线得(x1+x](/uploads/image/z/13963512-48-2.jpg?t=%E6%8A%9B%E7%89%A9%E7%BA%BFC1+y%2A2%3D4x+%E7%9A%84%E7%84%A6%E7%82%B9F%E6%81%B0%E5%A5%BD%E6%98%AF%E5%8F%8C%E6%9B%B2%E7%BA%BFC2+x%2A2%2Fa%2A2-y%2A2%2Fb%2A2%3D1%28a%3E0%2Cb%3E0%29%E7%9A%84%E5%8F%B3%E7%84%A6%E7%82%B9%2C%E4%B8%94C1%E4%B8%8EC2%E7%84%A6%E7%82%B9%E7%9A%84%E8%BF%9E%E7%BA%BF%E8%BF%87%E7%82%B9F%2C%E5%88%99%E5%8F%8C%E6%9B%B2%E7%BA%BFC2%E7%9A%84%E7%A6%BB%E5%BF%83%E7%8E%87%E6%98%AF%E5%A4%9A%E5%B0%91y%2A2%3D4xx%2A2%2Fa%2A2-y%2A2%2Fb%2A2%3D1%E8%81%94%E7%AB%8B%E5%BE%97b%2A2x%2A2-4a%2A2x-a%2A2b%2A2%3D0%E6%89%80%E4%BB%A5x1%2Bx2%3D4a%2A2%2Fb%2A2%E7%94%B1%E6%8A%9B%E7%89%A9%E7%BA%BF%E5%BE%97%28x1%2Bx)
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