one-to-one function g and h are defined as follows.g={(-6,5),(0,6)(2,0),(3,-7)} h(x)=8x+3find the following1.g^-1(0)=2.h^-1(x)=3.(h.h^-1)(-5)=

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one-to-one function g and h are defined as follows.g={(-6,5),(0,6)(2,0),(3,-7)} h(x)=8x+3find the following1.g^-1(0)=2.h^-1(x)=3.(h.h^-1)(-5)=
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one-to-one function g and h are defined as follows.g={(-6,5),(0,6)(2,0),(3,-7)} h(x)=8x+3find the following1.g^-1(0)=2.h^-1(x)=3.(h.h^-1)(-5)=
one-to-one function g and h are defined as follows.g={(-6,5),(0,6)(2,0),(3,-7)} h(x)=8x+3
find the following1.g^-1(0)=
2.h^-1(x)=
3.(h.h^-1)(-5)=

one-to-one function g and h are defined as follows.g={(-6,5),(0,6)(2,0),(3,-7)} h(x)=8x+3find the following1.g^-1(0)=2.h^-1(x)=3.(h.h^-1)(-5)=
g(x)={(-6,5),(0,6)(2,0),(3,-7)}
g^-1(x)={(5,-6),(6,0)(0,2),(-7,3)}
g^-1(0)=2
y=8x+3
x=(y-3)/8
h^-1(x)=(x-3)/8
h.h^-1这个表示什么h(x)*h^-1(x)吗?
(h.h^-1)(-5)=[8*(-5)+3]*[(-5-3)/8]=37

1 g(2)=0 so g^-1(0)=2
2 h(x)=8x+3 then x = 1/8*(h(x)-3) so h^-1(x)=1/8*(x-3)
3 (h*h^-1)(x) = (8x+3) * (1/8*(x-3)) = 1/8(x-3)(8x+3) then (h.h^-1)(-5)=37

什么叫one- to -one function?如何判定是否one- to -one function? 英语翻译in order to have a inverse function,the function must be one-to-one,but why the sine function has a inverse function? from one to one error C2564:'int' :function-style conversion to builtin type takes only one argument. one to one to 英语翻译one half to one one one's way to ONE one one one one one one ONE One one