2x^2-10/x/-28=0

一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 4x²+5x=81 x(x+5)=0 (2x-x)(x-1)=0 x(x+5)=5x-10 (3x-2)(x+1)=x(2x-1) f(x)={x^2-2x,x>=0 x^2+2x,x (x+12)(x-2)+(x+7)(x+8)-(x+5)(x-10),其中x=2 如果X*X--1=0,那么X*X*X+2*X*X+2008=几? 已知x*x+x-1=0 求x*x*x-2x+11=? 已知x*x+x-1=0求x*x*x-2x+2010的值 1/x+1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+...1/(x+9)(x+10)=0 解方程:1/x+1/x(x+1)+1/(x+1)(x+2)+1/(x+2)(x+3)+……+1/(x+9)(x+10)=0 （2x-2）(x-1)=0 x(x-5)=5x-10 计算x^2+6x+9/x^3-7x^2+10x>=0 解方程(x/x(x+2))+(x/(x+2)(x+4))+.+x/(x+8)(x+10)=1 2的x次方+x=0求x2^x+x=10求x X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4) x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 x^2+10x( )=(x+ )^2 x^2-10x=2-x x(x-2)+x-2=0