不定积分∫(e∧x-1)/(e∧x+1)等于,麻烦给出过程.

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 16:39:13
不定积分∫(e∧x-1)/(e∧x+1)等于,麻烦给出过程.
xn@_ŊT)!My(SAD*hllH.QZwjܾ3gа`>3Hwq>yq>X'GlQ|zy1ۿ}5;-v?o叽bJw@?hdYPK> sMvhPG'i< 3=$ {6x' xüĆdk`C(&M44m p!!u(11'&A"Z4&Lr+эX̽a:s]ӃZcSڝ'ٳ' VwKfzT*%,UeoG-m^^σ_goaZ~?A UwG䒊W Nua- Pf,ZGk

不定积分∫(e∧x-1)/(e∧x+1)等于,麻烦给出过程.
不定积分∫(e∧x-1)/(e∧x+1)等于,麻烦给出过程.

不定积分∫(e∧x-1)/(e∧x+1)等于,麻烦给出过程.

∫ (e^x - 1)/(e^x + 1) dx
= ∫ (e^x + 1 - 2)/(e^x + 1) dx
= ∫ dx - 2∫ dx/(e^x + 1)
= x - 2∫ e^x/[e^x(e^x + 1)] dx
= x - 2∫ (e^x + 1 - e^x)/[e^x(e^x + 1)] d(e^x)
= x - 2∫ 1/e^x d(e^x)...

全部展开

∫ (e^x - 1)/(e^x + 1) dx
= ∫ (e^x + 1 - 2)/(e^x + 1) dx
= ∫ dx - 2∫ dx/(e^x + 1)
= x - 2∫ e^x/[e^x(e^x + 1)] dx
= x - 2∫ (e^x + 1 - e^x)/[e^x(e^x + 1)] d(e^x)
= x - 2∫ 1/e^x d(e^x) + 2∫ 1/(e^x + 1) d(e^x + 1)
= x - 2ln(e^x) + 2ln(1 + e^x) + C
= x - 2ln[e^x/(1 + e^x)] + C
= x + 2ln[1 + e^(- x)] + C

收起

原式=∫ [e^x/(e^x+1)-1/(e^x+1)]dx
=∫d(e^x)/(e^x+1)- ∫ d(e^x)/[e^x(e^x+1)]
=ln(e^x+1)-∫d(e^x)*[1/e^x-1/(e^x+1)]
=ln(e^x+1)-lne^x+ln(e^x+1)+C
=2ln(e^x+1)-x+C