实数x,y满足(更号下x²+1997-x)(根号下y²+1997-y)=1997,求x+y的值.(根号下x²+1997-x到1997就没根号了(根号下y²+1997-y也是到y就没根号了

来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 18:56:36
实数x,y满足(更号下x²+1997-x)(根号下y²+1997-y)=1997,求x+y的值.(根号下x²+1997-x到1997就没根号了(根号下y²+1997-y也是到y就没根号了
x){n޳*t*^b{:jʆچt$HV"KV%mA,g*+jyڰGY=aO;6O7l|i!Tͮ6?9ٌ@]hZli~G4-TU W Wj**8`:^U;T>nS0%*4 5FcՆb(VZa1@2}ӱi0B4!4;@mgxڵizv~qAb(%v޹

实数x,y满足(更号下x²+1997-x)(根号下y²+1997-y)=1997,求x+y的值.(根号下x²+1997-x到1997就没根号了(根号下y²+1997-y也是到y就没根号了
实数x,y满足(更号下x²+1997-x)(根号下y²+1997-y)=1997,求x+y的值.
(根号下x²+1997-x到1997就没根号了(根号下y²+1997-y也是到y就没根号了

实数x,y满足(更号下x²+1997-x)(根号下y²+1997-y)=1997,求x+y的值.(根号下x²+1997-x到1997就没根号了(根号下y²+1997-y也是到y就没根号了
(√(x²+1997) - x)(√(y²+1997) - y) = 1997
所以√(x²+1997) - x = 1997/(√(y²+1997) - y) = √(y²+1997) + y (1)
√(y²+1997) - y = 1997/(√(x²+1997) - x) = √(x²+1997) + x (2)
由(1)得√(x²+1997) - √(y²+1997) = x+y
由(2)得√(y²+1997) - √(x²+1997) = x+y
再相加可得x+y=0