正方形ABCD中,O是AC与BD的交点,∠DAC的平分线AP交CD于P,∠BDC的角平分线DQ交AC于Q,求BD\CD=AP\BQ
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![正方形ABCD中,O是AC与BD的交点,∠DAC的平分线AP交CD于P,∠BDC的角平分线DQ交AC于Q,求BD\CD=AP\BQ](/uploads/image/z/14113733-5-3.jpg?t=%E6%AD%A3%E6%96%B9%E5%BD%A2ABCD%E4%B8%AD%2CO%E6%98%AFAC%E4%B8%8EBD%E7%9A%84%E4%BA%A4%E7%82%B9%2C%E2%88%A0DAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BFAP%E4%BA%A4CD%E4%BA%8EP%2C%E2%88%A0BDC%E7%9A%84%E8%A7%92%E5%B9%B3%E5%88%86%E7%BA%BFDQ%E4%BA%A4AC%E4%BA%8EQ%2C%E6%B1%82BD%5CCD%3DAP%5CBQ)
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