a+b+c=0,求a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)的值,我做到这做不下去了由条件得a=-(b+c)因为2a^2+bc=a^2+a^2+bc所以 =a^2-(b+c)a+bc=(a-b)(a-c)同理,2b^2+ac=(b-a)(b-c)2c^2+ab=(c-a)(c-b)所以,原式=a^2/(a-b)(a-c)+b^2/(b-a)(b-
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![a+b+c=0,求a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)的值,我做到这做不下去了由条件得a=-(b+c)因为2a^2+bc=a^2+a^2+bc所以 =a^2-(b+c)a+bc=(a-b)(a-c)同理,2b^2+ac=(b-a)(b-c)2c^2+ab=(c-a)(c-b)所以,原式=a^2/(a-b)(a-c)+b^2/(b-a)(b-](/uploads/image/z/14201216-8-6.jpg?t=a%2Bb%2Bc%3D0%2C%E6%B1%82a%5E2%2F%282a%5E2%2Bbc%29+%2B+b%5E2%2F%282b%5E2%2Bac%29+%2B+c%5E2%2F%282c%5E2%2Bab%29%E7%9A%84%E5%80%BC%2C%E6%88%91%E5%81%9A%E5%88%B0%E8%BF%99%E5%81%9A%E4%B8%8D%E4%B8%8B%E5%8E%BB%E4%BA%86%E7%94%B1%E6%9D%A1%E4%BB%B6%E5%BE%97a%3D-%28b%2Bc%29%E5%9B%A0%E4%B8%BA2a%5E2%2Bbc%3Da%5E2%2Ba%5E2%2Bbc%E6%89%80%E4%BB%A5+%3Da%5E2-%28b%2Bc%29a%2Bbc%3D%28a-b%29%28a-c%29%E5%90%8C%E7%90%86%2C2b%5E2%2Bac%3D%28b-a%29%28b-c%292c%5E2%2Bab%3D%28c-a%29%28c-b%29%E6%89%80%E4%BB%A5%2C%E5%8E%9F%E5%BC%8F%3Da%5E2%2F%28a-b%29%28a-c%29%2Bb%5E2%2F%28b-a%29%28b-)
a+b+c=0,求a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)的值,我做到这做不下去了由条件得a=-(b+c)因为2a^2+bc=a^2+a^2+bc所以 =a^2-(b+c)a+bc=(a-b)(a-c)同理,2b^2+ac=(b-a)(b-c)2c^2+ab=(c-a)(c-b)所以,原式=a^2/(a-b)(a-c)+b^2/(b-a)(b-
a+b+c=0,求a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)的值,我做到这做不下去了
由条件得
a=-(b+c)
因为2a^2+bc=a^2+a^2+bc
所以 =a^2-(b+c)a+bc
=(a-b)(a-c)
同理,2b^2+ac=(b-a)(b-c)
2c^2+ab=(c-a)(c-b)
所以,原式=a^2/(a-b)(a-c)+b^2/(b-a)(b-c)+c^2/(c-a)(c-b)
{变号} =a^2/(a-b)(a-c)-b^2/(a-b)(b-c)+c^2/(a-c)(b-c)
然后就做不下去了,
a+b+c=0,求a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)的值,我做到这做不下去了由条件得a=-(b+c)因为2a^2+bc=a^2+a^2+bc所以 =a^2-(b+c)a+bc=(a-b)(a-c)同理,2b^2+ac=(b-a)(b-c)2c^2+ab=(c-a)(c-b)所以,原式=a^2/(a-b)(a-c)+b^2/(b-a)(b-
∵a+b+c=0
∴b+c=a,a+c=b,a+b=c
a^2/(2a^2+bc) + b^2/(2b^2+ac) + c^2/(2c^2+ab)
=a^2/(2a^2-a)+ b^2/(2b^2-b) + c^2/(2c^2-c)
=a/(2a-1)+ b/(2-1) + c/(2c-1)
我只会做到这儿了,你在想想吧
望而生畏