1/(a-1)=1/(a^2-1)x 1/(x-1)+1/(1+x)(-z)/(-xy)=____(-5-y)/(-x)=_____分式方程(x)/(x-3)+1=m/(x-3)有增根,则m等于( )------------------------回答题目要写过程-------------------------
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![1/(a-1)=1/(a^2-1)x 1/(x-1)+1/(1+x)(-z)/(-xy)=____(-5-y)/(-x)=_____分式方程(x)/(x-3)+1=m/(x-3)有增根,则m等于( )------------------------回答题目要写过程-------------------------](/uploads/image/z/14226233-41-3.jpg?t=1%2F%28a-1%29%3D1%2F%28a%5E2-1%29x+1%2F%28x-1%29%2B1%2F%281%2Bx%29%28-z%29%2F%28-xy%29%3D____%28-5-y%29%2F%28-x%29%3D_____%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%28x%29%2F%28x-3%29%2B1%3Dm%2F%28x-3%29%E6%9C%89%E5%A2%9E%E6%A0%B9%2C%E5%88%99m%E7%AD%89%E4%BA%8E%EF%BC%88+%EF%BC%89------------------------%E5%9B%9E%E7%AD%94%E9%A2%98%E7%9B%AE%E8%A6%81%E5%86%99%E8%BF%87%E7%A8%8B-------------------------)
1/(a-1)=1/(a^2-1)x 1/(x-1)+1/(1+x)(-z)/(-xy)=____(-5-y)/(-x)=_____分式方程(x)/(x-3)+1=m/(x-3)有增根,则m等于( )------------------------回答题目要写过程-------------------------
1/(a-1)=1/(a^2-1)
x
1/(x-1)+1/(1+x)
(-z)/(-xy)=____
(-5-y)/(-x)=_____
分式方程(x)/(x-3)+1=m/(x-3)有增根,则m等于( )
------------------------回答题目要写过程-------------------------
1/(a-1)=1/(a^2-1)x 1/(x-1)+1/(1+x)(-z)/(-xy)=____(-5-y)/(-x)=_____分式方程(x)/(x-3)+1=m/(x-3)有增根,则m等于( )------------------------回答题目要写过程-------------------------
第三个不懂你什么意思
1. 可以交叉向乘,得:a^2-1=a-1
a^2-a=0 a=0或a=1(舍去) 因为分母不能为0
所以a=0
2. 通分: 原式= (x+1)/(x^2-1)+(x-1)/(x^2-1)
= x^2/(x^2-1)
4. 两边同乘(x-3) 得: x+x-3=m
m=2x-3
出现增根唯一可能是x=3 即,分母为0
所以m=3