在三角形ABC中,角C=90°,点D是AB上一点,DE垂直BC,垂足是E,且BE=AC,若BD=0.5,DE+BC=1,求证:角ABC=30°
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![在三角形ABC中,角C=90°,点D是AB上一点,DE垂直BC,垂足是E,且BE=AC,若BD=0.5,DE+BC=1,求证:角ABC=30°](/uploads/image/z/14246387-35-7.jpg?t=%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E8%A7%92C%3D90%C2%B0%2C%E7%82%B9D%E6%98%AFAB%E4%B8%8A%E4%B8%80%E7%82%B9%2CDE%E5%9E%82%E7%9B%B4BC%2C%E5%9E%82%E8%B6%B3%E6%98%AFE%2C%E4%B8%94BE%3DAC%2C%E8%8B%A5BD%3D0.5%2CDE%2BBC%3D1%2C%E6%B1%82%E8%AF%81%EF%BC%9A%E8%A7%92ABC%3D30%C2%B0)
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