求方程的根,用三个函数分别求当b^2-4ac大于0、等于0、和小于0时的根,并输出结果.从主函数输入a、b、c#include#includefloat p,q;void m(int a,int b,int c,float d){\x05p=(-b+sqrt(d))/(2*a);\x05q=(-b-sqrt(d))/(2*a);\x05pri
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![求方程的根,用三个函数分别求当b^2-4ac大于0、等于0、和小于0时的根,并输出结果.从主函数输入a、b、c#include#includefloat p,q;void m(int a,int b,int c,float d){\x05p=(-b+sqrt(d))/(2*a);\x05q=(-b-sqrt(d))/(2*a);\x05pri](/uploads/image/z/14253890-50-0.jpg?t=%E6%B1%82%E6%96%B9%E7%A8%8B%E7%9A%84%E6%A0%B9%2C%E7%94%A8%E4%B8%89%E4%B8%AA%E5%87%BD%E6%95%B0%E5%88%86%E5%88%AB%E6%B1%82%E5%BD%93b%5E2-4ac%E5%A4%A7%E4%BA%8E0%E3%80%81%E7%AD%89%E4%BA%8E0%E3%80%81%E5%92%8C%E5%B0%8F%E4%BA%8E0%E6%97%B6%E7%9A%84%E6%A0%B9%2C%E5%B9%B6%E8%BE%93%E5%87%BA%E7%BB%93%E6%9E%9C.%E4%BB%8E%E4%B8%BB%E5%87%BD%E6%95%B0%E8%BE%93%E5%85%A5a%E3%80%81b%E3%80%81c%23include%23includefloat+p%2Cq%3Bvoid+m%28int+a%2Cint+b%2Cint+c%2Cfloat+d%29%7B%5Cx05p%3D%28-b%2Bsqrt%28d%29%29%2F%282%2Aa%29%3B%5Cx05q%3D%28-b-sqrt%28d%29%29%2F%282%2Aa%29%3B%5Cx05pri)
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