已知函数f(x)=2√3sinxcosx+2cos²x-1(x∈R)1.求函数f(x)的最小正周期及在区间[0,π/2]的最大和最小值 2.若f(x0)=6/5,x0∈[π/4,π/2],求cos2x0的值
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![已知函数f(x)=2√3sinxcosx+2cos²x-1(x∈R)1.求函数f(x)的最小正周期及在区间[0,π/2]的最大和最小值 2.若f(x0)=6/5,x0∈[π/4,π/2],求cos2x0的值](/uploads/image/z/14289761-65-1.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3D2%E2%88%9A3sinxcosx%2B2cos%26sup2%3Bx-1%EF%BC%88x%E2%88%88R%EF%BC%891.%E6%B1%82%E5%87%BD%E6%95%B0f%EF%BC%88x%29%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E5%8F%8A%E5%9C%A8%E5%8C%BA%E9%97%B4%5B0%2C%CF%80%2F2%5D%E7%9A%84%E6%9C%80%E5%A4%A7%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC+2.%E8%8B%A5f%EF%BC%88x0%EF%BC%89%3D6%2F5%2Cx0%E2%88%88%5B%CF%80%2F4%2C%CF%80%2F2%5D%2C%E6%B1%82cos2x0%E7%9A%84%E5%80%BC)
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