以三角形ABC的边AC、AB为边向外作正方形ABEF和正方形ACGH,fm=mh,D为BC边上任意一点,DA的延长线交FH于M,求证:AD垂直BC于D
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![以三角形ABC的边AC、AB为边向外作正方形ABEF和正方形ACGH,fm=mh,D为BC边上任意一点,DA的延长线交FH于M,求证:AD垂直BC于D](/uploads/image/z/14295157-61-7.jpg?t=%E4%BB%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E8%BE%B9AC%E3%80%81AB%E4%B8%BA%E8%BE%B9%E5%90%91%E5%A4%96%E4%BD%9C%E6%AD%A3%E6%96%B9%E5%BD%A2ABEF%E5%92%8C%E6%AD%A3%E6%96%B9%E5%BD%A2ACGH%2Cfm%3Dmh%2CD%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E4%BB%BB%E6%84%8F%E4%B8%80%E7%82%B9%2CDA%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4FH%E4%BA%8EM%2C%E6%B1%82%E8%AF%81%3AAD%E5%9E%82%E7%9B%B4BC%E4%BA%8ED)
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