数列{an}满足a1=1,an+1-an=n, 求该数列的通项公式an(下标不能打,可查看图片)
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数列{an}满足a1=1,an+1-an=n, 求该数列的通项公式an(下标不能打,可查看图片)
数列{an}满足a1=1,an+1-an=n, 求该数列的通项公式an(下标不能打,可查看图片)
数列{an}满足a1=1,an+1-an=n, 求该数列的通项公式an(下标不能打,可查看图片)
因为an+1-an=n 则a2-a1=1 a2=a1+1=2
且an-a(n-1)=n-1 (括号内为下标)
a(n-1)-a(n-2)=n-2
.
a2-a1=1
上述式子相加得
an-a1=n(n-1)/2
所以an=n(n-1)/2+1
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