如题
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/11 23:13:42
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如题
如题
如题
原式
=x²/(x-5)-25/(x-5)
=(x²-25)/(x-5)
=(x+5)(x-5)/(x-5)
=x+5
望采纳
你这是要通分吗?
原式=x^2/(x-5)-25/(x-5)
=(x^2-25)/(x-5)
=(x-5)(x+5)/(x-5)
=x+5.
x²-25/x-5
x-5
你明白了么? 把+号变成减号进行运算
(x+5)/(x-5)
x^2/(x-5)+25/(5-x)
=x^2/(x-5)-25/(5-x)
=( x^2-25)/(x-5)
=(x+5)(x-5)/(x-5)
=x+5 x不等于5
5-x=-(x-5)
∴原式=x²/(x-5)-25/(x-5)
=(x²-25)/(x-5)
=(x+5)(x-5)/(x-5)
=x+5
望采纳 谢谢