已知x与-2y互为相反数,y与3z互为相反数已知:x与-2y互为相反数,y与3z互为相反数,求1\2x-y+6z+3的值
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![已知x与-2y互为相反数,y与3z互为相反数已知:x与-2y互为相反数,y与3z互为相反数,求1\2x-y+6z+3的值](/uploads/image/z/14301881-17-1.jpg?t=%E5%B7%B2%E7%9F%A5x%E4%B8%8E-2y%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2Cy%E4%B8%8E3z%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%E5%B7%B2%E7%9F%A5%EF%BC%9Ax%E4%B8%8E-2y%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2Cy%E4%B8%8E3z%E4%BA%92%E4%B8%BA%E7%9B%B8%E5%8F%8D%E6%95%B0%2C%E6%B1%821%5C2x-y%2B6z%2B3%E7%9A%84%E5%80%BC)
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已知x与-2y互为相反数,y与3z互为相反数已知:x与-2y互为相反数,y与3z互为相反数,求1\2x-y+6z+3的值
已知x与-2y互为相反数,y与3z互为相反数
已知:x与-2y互为相反数,y与3z互为相反数,求1\2x-y+6z+3的值
已知x与-2y互为相反数,y与3z互为相反数已知:x与-2y互为相反数,y与3z互为相反数,求1\2x-y+6z+3的值
x与-2y互为相反数,y与3z互为相反数
所以x=2y
y=-3z
则x=-6z
所以原式=-3z+3z+6z+3=6z+3
你写错了吧
x与-2y互为相反数
x-2y=0
x=2y
y与3z互为相反数
y+3z=0
1\2x+y+6z+3
=1/2*2y+y+6z+3
=2y+6z+3
=2(y+3z)+3
=3
原式应该是:
1\2x+y+6z+3