fx=x²-2x+3 x∈[a,a+3] 求值域
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fx=x²-2x+3 x∈[a,a+3] 求值域
fx=x²-2x+3 x∈[a,a+3] 求值域
fx=x²-2x+3 x∈[a,a+3] 求值域
因为fx=(x-1)^2+2,即x=1时,f有极小值2,即x1时,f递增.
故a>1时,1不在【a,a+3】区间内并大于1,递增,故值域为【f(a),f(a+3)】
a+3