若线段x ,y 满足[2x-3y]*[3x+2y]=0 则x/y=?怎样算出2x-3y=0或3x+2y=0 当2x-3y=0时,x/y=3/2 当3x+2y=0时,x/y

若线段x ,y 满足[2x-3y]*[3x+2y]=0 则x/y=? 若线段x ,y 满足[2x-3y]*[3x+2y]=0 则x/y=?怎样算出2x-3y=0或3x+2y=0 当2x-3y=0时,x/y=3/2 当3x+2y=0时,x/y 若变量x,y满足约束条件{x>=-1;y>=x;3x+2y 几道比例线段题目已知两实数a,b满足a^2-4ab+4b^=0,求(a+b)/a已知x/2=y/3,求(x-y)/y ,(x+y)/y ,(x+y)/(x-y) 变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y 若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y= 若x,y满足|x-y+1|+(x+y+3)^2=0则x^2-y^2= 若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值 设变量x.y满足条件3x+2y 当x,y满足条件|x+3|+|y-2| 已知线段x,y的长度满足2x-3y=0求x-y:x+y一共3个还是4个答案 请都写出来 是关于比例线段的 若x,y为正整数,且满足3x(x+y)-y(x+y)=7,求x,y (1/2)已知实数x,y,a满足：根号(x+y-8)+根号(8-x-y)=根号(3x-y-a)+根号(x-2y+a+3),问长度分别为的三条线段 解答初三数学题啊{ x+y=z+x=y+z 2 3 4 分数线我就不打了）设线段X.Y.Z满足 { x+y+z=27 求x.y.z.的值 若实数x,y满足约束条件x-y-2=0,2y-3 比例线段：已知x/y=2/3,则 x/x+y= ,x-y/x+y= 要过程! 满足3x+4y 若x,y满足y