已知两组数x1,x2······,xn和y1,y2,······,yn它们的平均数分别是A,B,求下列各组数的平均数:(1)x1-y1,x2-y2······xn-yn:(2)x1,y1,x2,y2,······xn,yn.
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已知两组数x1,x2······,xn和y1,y2,······,yn它们的平均数分别是A,B,求下列各组数的平均数:(1)x1-y1,x2-y2······xn-yn:(2)x1,y1,x2,y2,······xn,yn.
已知两组数x1,x2······,xn和y1,y2,······,yn它们的平均数分别是A,B,求下列各组数的平均数:
(1)x1-y1,x2-y2······xn-yn:
(2)x1,y1,x2,y2,······xn,yn.
已知两组数x1,x2······,xn和y1,y2,······,yn它们的平均数分别是A,B,求下列各组数的平均数:(1)x1-y1,x2-y2······xn-yn:(2)x1,y1,x2,y2,······xn,yn.
1.(x1-y1+x2-y2······xn-yn)/n=(x1+x2······+xn)/n-(y1+y2+······+yn)/n=A-B
2.(x1+y1+x2+y2,······xn+yn)/2n=(x1+x2······+xn)/2n+(y1+y2+······+yn)/2n=(A+B)/2
A-B
A/2+B/2 除以2n
1,全加在一起,除以n,等于A-B
2、全加在一起,除以n,等于A+B
A=(x1+x2+···+xn)/n
B=(y1+y2+···+yn)/n
( x1-y1+x2-y2+···+xn-yn)/n
=[(x1+x2+···+xn)-(y1+y2+···+yn)]/n
=(x1+x2+···+xn)/n - (y1+y2+···+yn)/n
=A-B
( x1+y1+x2+y2+···+xn+yn)/n
=[(x1+x2+···+xn)+(y1+y2+···+yn)]/n
=(x1+x2+···+xn)/n + (y1+y2+···+yn)/n
=A+B