'initializing' :cannot convert from 'class A *' to 'class B *'int main(){A aa;B *pb=&aa;pb->g();return 0;}#includeclass A{public:void virtual g(){cout

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'initializing' :cannot convert from 'class A *' to 'class B *'int main(){A aa;B *pb=&aa;pb->g();return 0;}#includeclass A{public:void virtual g(){cout
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'initializing' :cannot convert from 'class A *' to 'class B *'int main(){A aa;B *pb=&aa;pb->g();return 0;}#includeclass A{public:void virtual g(){cout
'initializing' :cannot convert from 'class A *' to 'class B *'
int main()
{
A aa;
B *pb=&aa;
pb->g();
return 0;
}
#include
class A
{
public:
void virtual g(){cout

'initializing' :cannot convert from 'class A *' to 'class B *'int main(){A aa;B *pb=&aa;pb->g();return 0;}#includeclass A{public:void virtual g(){cout
A是B的父类,所以B的指针可以赋值给A的指针,但是A的指针不能赋值给B的指针,你这个正好搞反了,可以这样:
B bb;
A *pa = &bb;
pa->g(); // 相当于bb.g();