英语翻译∴$\left\{\begin{array}{l}{1-2{k}^{2}≠0}\\{△={16k}^{2}+16({1-2k}^{2})=16(1-{k}^{2})\;>0}\end{array}\right.$解得:-1<k<1且k≠±$\frac{\sqrt{2}}{2}$.(2)设A(x1,y1),B(x2,y2),则x1+x2=$\frac{4k}{1-2k^{2}}
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![英语翻译∴$\left\{\begin{array}{l}{1-2{k}^{2}≠0}\\{△={16k}^{2}+16({1-2k}^{2})=16(1-{k}^{2})\;>0}\end{array}\right.$解得:-1<k<1且k≠±$\frac{\sqrt{2}}{2}$.(2)设A(x1,y1),B(x2,y2),则x1+x2=$\frac{4k}{1-2k^{2}}](/uploads/image/z/14396012-44-2.jpg?t=%E8%8B%B1%E8%AF%AD%E7%BF%BB%E8%AF%91%E2%88%B4%24%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7D%7B1-2%7Bk%7D%5E%7B2%7D%E2%89%A00%7D%5C%5C%7B%E2%96%B3%3D%7B16k%7D%5E%7B2%7D%2B16%EF%BC%88%7B1-2k%7D%5E%7B2%7D%EF%BC%89%3D16%EF%BC%881-%7Bk%7D%5E%7B2%7D%EF%BC%89%5C%3B%EF%BC%9E0%7D%5Cend%7Barray%7D%5Cright.%24%E8%A7%A3%E5%BE%97%EF%BC%9A-1%EF%BC%9Ck%EF%BC%9C1%E4%B8%94k%E2%89%A0%C2%B1%24%5Cfrac%7B%5Csqrt%7B2%7D%7D%7B2%7D%24%EF%BC%8E%EF%BC%882%EF%BC%89%E8%AE%BEA%EF%BC%88x1%2Cy1%EF%BC%89%2CB%EF%BC%88x2%2Cy2%EF%BC%89%2C%E5%88%99x1%2Bx2%3D%24%5Cfrac%7B4k%7D%7B1-2k%5E%7B2%7D%7D)
英语翻译∴$\left\{\begin{array}{l}{1-2{k}^{2}≠0}\\{△={16k}^{2}+16({1-2k}^{2})=16(1-{k}^{2})\;>0}\end{array}\right.$解得:-1<k<1且k≠±$\frac{\sqrt{2}}{2}$.(2)设A(x1,y1),B(x2,y2),则x1+x2=$\frac{4k}{1-2k^{2}}
英语翻译
∴$\left\{\begin{array}{l}{1-2{k}^{2}≠0}\\{△={16k}^{2}+16({1-2k}^{2})=16(1-{k}^{2})\;>0}\end{array}\right.$
解得:-1<k<1且k≠±$\frac{\sqrt{2}}{2}$.
(2)设A(x1,y1),B(x2,y2),则x1+x2=$\frac{4k}{1-2k^{2}}$
设P为AB中点,则P($\frac{x_{1}+x_{2}}{2}$,$\frac{k(x_{1}+x_{2})}{2}$+1),即P($\frac{2k}{1-2k^{2}}$,$\frac{1}{1-2k^{2}}$),
∵M(3,0)到A、B两点的距离相等,
∴MP⊥AB,∴KMP•KAB=-1,
即k•$\frac{\frac{1}{{1-2k}^{2}}}{\frac{2k}{{1-2k}^{2}}-3}$=-1,解得k=$\frac{1}{2}$,或k=-1(舍去),
∴k=$\frac{1}{2}$.
英语翻译∴$\left\{\begin{array}{l}{1-2{k}^{2}≠0}\\{△={16k}^{2}+16({1-2k}^{2})=16(1-{k}^{2})\;>0}\end{array}\right.$解得:-1<k<1且k≠±$\frac{\sqrt{2}}{2}$.(2)设A(x1,y1),B(x2,y2),则x1+x2=$\frac{4k}{1-2k^{2}}
我觉得这个代表一个函数,可能因为一些错误,误把代码打了出来,这些代码代表的就是一个函数