作业帮sin(x + π/6）cos（π/3 - x）的最小正周期怎么算?
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sin(x + π/6）cos（π/3 - x）的最小正周期怎么算?
sin(x + π/6）cos（π/3 - x）的最小正周期怎么算?
sin(x + π/6）cos（π/3 - x）的最小正周期怎么算?
cos[π/2-(π/3+x)]=cos(π/6-x)=sin(π/3+x)
y=sin(x+π/3)cos(π/6-x)
=sin(x+π/3)sin(π/3+x)
=sin²(π/3+x)
=[1-cos(2π/3+2x)]/2
=1/2-1/2cos(2π/3+2x)
T=2π/2=π
sin cos之间怎么转换?sin(π/3-2X）等于cos多少?
cos(x+π/3)是不是等于sin(x-π/6)
cos(π/6-x)=sin(π/3+x)?为什么
求证 tan（2π-X）sin（-2π-X）cos（6π-X）/ sin（X+3π/2)*cos（X+3π/2)=-tanX
tanx=m,则{sin(x+3π）+cos(π+x)}/{sin(-x)-cos(π+x）}=?
sin(x+π/3)+（tanπ/6）cos(x+π/3) 化简 sin(x+π/3)+（tanπ/6）cos(x+π/3) 化简
已知函数f（x）=［2sin（x-π/6）+√3sin x］cos x+sin^2x,x∈R
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若sin(π+x)+cos(π/2+x)=-m,则cos（3π/2-π）+2sin（6π-x）=?
为什么cos(2x-π/3)-sin(5π/6) =cos(2x-π/3)?
化简sin(x+7π/4)+cos(x-3π/4）步骤我已经找到撒sin(x+7π/4)+cos(x-3π/4)=sin(x+2π-π/4)+cos(x-π+π/4)我问下这一步是在干嘛?=sin(x-π/4)+cos[-(π-x-π/4)]=sin(x-π/4)+cos(π-x-π/4)=sin(x-π/4)-cos(x+π/4)=sin(x-π/4)-cos(x+π/2-
sin（π/6+x）=1/3 cos（2π/3-2x）=?
sin（x-π/3）=1/3,则cos（x+π/6）=?
sin（x+π/6）=3/5,则cos(2x+π/3)=
化简：sin（π/3+4x）+cos（π/6-4x）
函数y=sin（x+π／3）cos（π/6-x）
sin(x + π/6）cos（π/3 - x）的最小正周期怎么算?