当x+y+z=2,x^2-(y+x)^2=8时,x-y-z=?

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当x+y+z=2,x^2-(y+x)^2=8时,x-y-z=?
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当x+y+z=2,x^2-(y+x)^2=8时,x-y-z=?
当x+y+z=2,x^2-(y+x)^2=8时,x-y-z=?

当x+y+z=2,x^2-(y+x)^2=8时,x-y-z=?
因为x^2-(y+x)^2=(x+y+z)(x-y-z)=8,x+y+z=2,
所以x-y-z=4