解下列一元二次方程【求过程】(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0(2)x² - 3|x| - 4 = 0(3)(x-3)² +(x+4)² -(x-5)² =17x+24
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![解下列一元二次方程【求过程】(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0(2)x² - 3|x| - 4 = 0(3)(x-3)² +(x+4)² -(x-5)² =17x+24](/uploads/image/z/14413115-11-5.jpg?t=%E8%A7%A3%E4%B8%8B%E5%88%97%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%E3%80%90%E6%B1%82%E8%BF%87%E7%A8%8B%E3%80%91%EF%BC%881%EF%BC%89x%26%23178%3B+%2B%EF%BC%881%2B2%E5%80%8D%E6%A0%B9%E5%8F%B73%EF%BC%89x+%2B+3+%2B+%E6%A0%B9%E5%8F%B73+%3D+0%EF%BC%882%EF%BC%89x%26%23178%3B+-+3%7Cx%7C+-+4+%3D+0%EF%BC%883%EF%BC%89%EF%BC%88x-3%EF%BC%89%26%23178%3B+%2B%EF%BC%88x%2B4%EF%BC%89%26%23178%3B+-%EF%BC%88x-5%EF%BC%89%26%23178%3B+%3D17x%2B24)
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解下列一元二次方程【求过程】(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0(2)x² - 3|x| - 4 = 0(3)(x-3)² +(x+4)² -(x-5)² =17x+24
解下列一元二次方程【求过程】
(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0
(2)x² - 3|x| - 4 = 0
(3)(x-3)² +(x+4)² -(x-5)² =17x+24
解下列一元二次方程【求过程】(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0(2)x² - 3|x| - 4 = 0(3)(x-3)² +(x+4)² -(x-5)² =17x+24
(1)x² +(1+2倍根号3)x + 3 + 根号3 = 0
(x+根号3)(x+1+根号3)=0
x1=-根号3,x2=-1-根号3.
(2)x² - 3|x| - 4 = 0
x>=0,x²-3x-4=0,(x+1(x-4)=0,x1=-1(舍去),x2=4.
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