已知a+b=-1,求aˇ3-3ab+bˇ3的值?

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已知a+b=-1,求aˇ3-3ab+bˇ3的值?
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已知a+b=-1,求aˇ3-3ab+bˇ3的值?
已知a+b=-1,求aˇ3-3ab+bˇ3的值?

已知a+b=-1,求aˇ3-3ab+bˇ3的值?
aˇ3-3ab+bˇ3
=(a+b)(a^2-ab+b^2-3ab)
=-a^2+ab-b^2-3ab
=1a^2-2ab-b^2
=-(a+b)^2
=-1

aˇ3-3ab+bˇ3
=a^3+b^3-3ab
=(a+b)(a^2-ab+b^2)-3ab
=-1*(a^2-ab+b^2)-3ab
=-a^2+ab-b^2-3ab
=-(a^2+2ab+b^2)
=-(a+b)^2
=-(-1)^2
=-1

A³+B³-3AB
=(A+B)(A²-AB+B²)-3AB
=-(A²-AB+B²)-3AB
=-A²+AB-B²-3AB
=-A²-2AB-B²
=-(A²+2AB+B²)
=-(A+B)²
=-(-1)&su...

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A³+B³-3AB
=(A+B)(A²-AB+B²)-3AB
=-(A²-AB+B²)-3AB
=-A²+AB-B²-3AB
=-A²-2AB-B²
=-(A²+2AB+B²)
=-(A+B)²
=-(-1)²
=-1

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答案1 先( a b) ^ 3得到a^3+3ab(a+b)+b^ 3,因为条件,所以是1

(a+b)^3=a^3+3a^2b+3ab^2+b^3=a^3+3a
b(a+b)+b^3 左右式带入a+b=-1 得原式=(-1)^3=-1