y"+y'-2y=2x

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y"+y'-2y=2x
y"+y'-2y=2x

y"+y'-2y=2x
y"+y'-2y=2x
先求 y"+y'-2y=0的通
r²+r-2=0,r=1或-2
y=ce^x+de^(-2x)
再求一个特解,
设特解为 y=ax+b,则y'=a,y"=0
代入原式得 0+a-2ax-2b=2x
可求得 -2a=2,a-2b=0,即a=-1,b=-1/2
特解是 y*=-x-1/2
所以方程的解是
y=ce^x+de^(-2x)-x-1/2

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 y+y'-2y=2x 微分方程y - 2y' + y = x 填空：x-y/x+y=( )/x^2-y^2 （x-y)2•(y-x)³(x-y)=? (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= (x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) 化简y(x+y)+(x+y)(x-y)-x^2 (x-4y)(2x+y)= (x+y)(2x-3y)=? x+y>=2,x-y x+y>=2,x-y y'-2y=(e^x)-x y'+2y/x=x通解 dy/dx=(2x*x*x*y-y*y*y*y)/(x*x*x*x-2x*y*y*y) 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=