已知x/y=2/7 则x^2-3xy+2y^2 / 2x^2-3xy+7y^2=?1/x+1/y=2 求2x-3xy+2y / 3x+3y+2xy=?已知x/y=2/7 则x^2-3xy+2y^2 / 2x^2-3xy+7y^2=?1/x+1/y=2 求2x-3xy+2y / 3x+3y+2xy=?
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![已知x/y=2/7 则x^2-3xy+2y^2 / 2x^2-3xy+7y^2=?1/x+1/y=2 求2x-3xy+2y / 3x+3y+2xy=?已知x/y=2/7 则x^2-3xy+2y^2 / 2x^2-3xy+7y^2=?1/x+1/y=2 求2x-3xy+2y / 3x+3y+2xy=?](/uploads/image/z/144637-61-7.jpg?t=%E5%B7%B2%E7%9F%A5x%2Fy%3D2%2F7+%E5%88%99x%5E2-3xy%2B2y%5E2+%2F+2x%5E2-3xy%2B7y%5E2%3D%3F1%2Fx%2B1%2Fy%3D2+%E6%B1%822x-3xy%2B2y+%2F+3x%2B3y%2B2xy%3D%3F%E5%B7%B2%E7%9F%A5x%2Fy%3D2%2F7+%E5%88%99x%5E2-3xy%2B2y%5E2+%2F+2x%5E2-3xy%2B7y%5E2%3D%3F1%2Fx%2B1%2Fy%3D2+%E6%B1%822x-3xy%2B2y+%2F+3x%2B3y%2B2xy%3D%3F)
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