|n-1|+|n-2|+...+|n-30|求最小值但是怎么证明,就有点头大了~1L乃显然做错了..........显然不解释......
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![|n-1|+|n-2|+...+|n-30|求最小值但是怎么证明,就有点头大了~1L乃显然做错了..........显然不解释......](/uploads/image/z/14494333-13-3.jpg?t=%7Cn-1%7C%2B%7Cn-2%7C%2B...%2B%7Cn-30%7C%E6%B1%82%E6%9C%80%E5%B0%8F%E5%80%BC%E4%BD%86%E6%98%AF%E6%80%8E%E4%B9%88%E8%AF%81%E6%98%8E%2C%E5%B0%B1%E6%9C%89%E7%82%B9%E5%A4%B4%E5%A4%A7%E4%BA%86%7E1L%E4%B9%83%E6%98%BE%E7%84%B6%E5%81%9A%E9%94%99%E4%BA%86..........%E6%98%BE%E7%84%B6%E4%B8%8D%E8%A7%A3%E9%87%8A......)
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|n-1|+|n-2|+...+|n-30|求最小值但是怎么证明,就有点头大了~1L乃显然做错了..........显然不解释......
|n-1|+|n-2|+...+|n-30|求最小值
但是怎么证明,就有点头大了~
1L乃显然做错了..........显然不解释......
|n-1|+|n-2|+...+|n-30|求最小值但是怎么证明,就有点头大了~1L乃显然做错了..........显然不解释......
相当于数轴上坐标N到坐标1、2、3……30的距离之和.
易知N在1、30的中间时,距离之和最小
N = 1 + (30-1)/2 = 15.5
|n-1|+|n-2|+...+|n-30|
= (15.5-1)+ (15.5-2)+……+(15.5-15)+(16-15.5)+(17-15.5)+……+(30-15.5)
= 29 + 27 + …… + 1
= (1+29)*15/2
= 225
=(/n-1/+/n-30/)*30/2
当n>=30时:=(2n-31)*15,当n=30时,最小 为 29*15
当1《=n《=30时:
当n《=1时:
根据范围去绝对值符号 , 再根据范围取值, 就明了了。
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