sin(π/3-x)=3/5,cos(5/6π-x)=-3/5cos(5/6π-x)=cos(x-5/6π)=-sin(x-2/6π)=sin(3/π-x)=3/5 为什么错了,哪个步骤错了
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![sin(π/3-x)=3/5,cos(5/6π-x)=-3/5cos(5/6π-x)=cos(x-5/6π)=-sin(x-2/6π)=sin(3/π-x)=3/5 为什么错了,哪个步骤错了](/uploads/image/z/14499278-62-8.jpg?t=sin%28%CF%80%2F3-x%29%3D3%2F5%2Ccos%285%2F6%CF%80-x%29%3D-3%2F5cos%285%2F6%CF%80-x%29%3Dcos%28x-5%2F6%CF%80%29%3D-sin%28x-2%2F6%CF%80%EF%BC%89%3Dsin%283%2F%CF%80-x%29%3D3%2F5+%E4%B8%BA%E4%BB%80%E4%B9%88%E9%94%99%E4%BA%86%2C%E5%93%AA%E4%B8%AA%E6%AD%A5%E9%AA%A4%E9%94%99%E4%BA%86)
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sin(π/3-x)=3/5,cos(5/6π-x)=-3/5cos(5/6π-x)=cos(x-5/6π)=-sin(x-2/6π)=sin(3/π-x)=3/5 为什么错了,哪个步骤错了
sin(π/3-x)=3/5,cos(5/6π-x)=-3/5
cos(5/6π-x)=cos(x-5/6π)=-sin(x-2/6π)=sin(3/π-x)=3/5 为什么错了,哪个步骤错了
sin(π/3-x)=3/5,cos(5/6π-x)=-3/5cos(5/6π-x)=cos(x-5/6π)=-sin(x-2/6π)=sin(3/π-x)=3/5 为什么错了,哪个步骤错了
cos(5/6π-x)
=cos(π/2+π/3-x)
=-sin(π/3-x))
对的啊。cos(5/6π-x)=3/5 但不是你最开始写的-3/5