1×2×3×4×····×141×142的积中,因数3的个数一共有几个

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1×2×3×4×····×141×142的积中,因数3的个数一共有几个
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1×2×3×4×····×141×142的积中,因数3的个数一共有几个
1×2×3×4×····×141×142的积中,因数3的个数一共有几个

1×2×3×4×····×141×142的积中,因数3的个数一共有几个
是不是存在多少个因数3,如果是的话应该是每隔一个3是可以整除3的.
3、6、9..138、141.
每一个除3得到的个数是1、2、3..46、47
相加：1+2+3+.+47=1128

基本概念题，因数的定义：假如整数n除以m，结果是无余数的整数，那么我们称m就是n的因数。需要注意的是，唯有被除数，除数，商皆为整数，余数为零时，此关系才成立。 反过来说，我们称n为m的倍数。

1×2×3×4×····×141×142的积除以3后，其结果只有一个，为1×2×4×····×141×142。...

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基本概念题，因数的定义：假如整数n除以m，结果是无余数的整数，那么我们称m就是n的因数。需要注意的是，唯有被除数，除数，商皆为整数，余数为零时，此关系才成立。 反过来说，我们称n为m的倍数。

1×2×3×4×····×141×142的积除以3后，其结果只有一个，为1×2×4×····×141×142。

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