请问y=3x²-6x+2怎么算出他的取值范围,大于0还是小于0?怎么求出y=根号x²-4x+9的定义域还有y=根号-2x²+12x-18的定义域,急用
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![请问y=3x²-6x+2怎么算出他的取值范围,大于0还是小于0?怎么求出y=根号x²-4x+9的定义域还有y=根号-2x²+12x-18的定义域,急用](/uploads/image/z/14573531-11-1.jpg?t=%E8%AF%B7%E9%97%AEy%3D3x%26%23178%3B-6x%2B2%E6%80%8E%E4%B9%88%E7%AE%97%E5%87%BA%E4%BB%96%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%2C%E5%A4%A7%E4%BA%8E0%E8%BF%98%E6%98%AF%E5%B0%8F%E4%BA%8E0%3F%E6%80%8E%E4%B9%88%E6%B1%82%E5%87%BAy%3D%E6%A0%B9%E5%8F%B7x%26%23178%3B-4x%2B9%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%E8%BF%98%E6%9C%89y%3D%E6%A0%B9%E5%8F%B7-2x%26%23178%3B%2B12x-18%E7%9A%84%E5%AE%9A%E4%B9%89%E5%9F%9F%2C%E6%80%A5%E7%94%A8)
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