f(x)在(0,正无穷大)上是增函数,满足f(xy)=f(x)+f(y) ,f(8)=3.解不等式f(x)+f(x-2)大于3
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 06:23:28
![f(x)在(0,正无穷大)上是增函数,满足f(xy)=f(x)+f(y) ,f(8)=3.解不等式f(x)+f(x-2)大于3](/uploads/image/z/14598334-46-4.jpg?t=f%28x%29%E5%9C%A8%EF%BC%880%2C%E6%AD%A3%E6%97%A0%E7%A9%B7%E5%A4%A7%EF%BC%89%E4%B8%8A%E6%98%AF%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E6%BB%A1%E8%B6%B3f%28xy%29%3Df%28x%29%2Bf%28y%29+%2Cf%288%29%3D3.%E8%A7%A3%E4%B8%8D%E7%AD%89%E5%BC%8Ff%28x%29%2Bf%28x-2%29%E5%A4%A7%E4%BA%8E3)
x)KӨ|:g=:.~6}۟.Y~O]fhϦny{m*5mAڴ4*5t4,4m^,_dGOCe+t4F=glTO7l30Ȁ8#]
M;c[ `!;0DSBH "kgcڋ
<;l`Q|dRn,l8p5(6T/_̜cu|:>L l 7
f(x)在(0,正无穷大)上是增函数,满足f(xy)=f(x)+f(y) ,f(8)=3.解不等式f(x)+f(x-2)大于3
f(x)在(0,正无穷大)上是增函数,满足f(xy)=f(x)+f(y) ,f(8)=3.解不等式f(x)+f(x-2)大于3
f(x)在(0,正无穷大)上是增函数,满足f(xy)=f(x)+f(y) ,f(8)=3.解不等式f(x)+f(x-2)大于3
f(x)+f(x-2)=f(x^2-2x)>3=f(8)
x^2-2x>8
(x-4)(x+2)>0
x>4或者x
f(x(x-2))>3=f(8)
所以
x(x-2)>8
所以(x+2)(x-4)>0
x>4或x<-2
考虑到定义域
x>4