已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2 B.12,-1 C.12,1 D.12,-1,1

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已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2 B.12,-1 C.12,1 D.12,-1,1
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已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2 B.12,-1 C.12,1 D.12,-1,1
已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2
已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2 B.12,-1 C.12,1
D.12,-1,1

已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2已知集合A={1,2a},B={a,b},若A∩B=12,则A∪B= A.12,1,2 B.12,-1 C.12,1 D.12,-1,1
因为A∩B=12,所以A中有12,即2a=12,a=6,则B中的b=12
所以A∪B= 1,6,12,哎呦没答案,郁闷